RossBencina14 hours ago
It is not just a way of writing ring buffers. It's a way of implementing concurrent non-blocking single-reader single-writer atomic ring buffers with only atomic load and store (and memory barriers).
The author says that non-power-of-two is not possible, but I'm pretty sure it is if you use a conditional instead of integer modulus.
I first learnt of this technique from Phil Burk, we've been using it in PortAudio forever. The technique is also widely known in FPGA/hardware circles, see:
"Simulation and Synthesis Techniques for Asynchronous FIFO Design", Clifford E. Cummings, Sunburst Design, Inc.
https://twins.ee.nctu.edu.tw/courses/ip_core_04/resource_pdf...
hinkley13 hours ago
I think unfortunately we sometimes ascribe to powers of two supernatural powers that are really about caches being built in powers of two.
Intel is still 64 byte cache lines as they have been for quite a long time but they also do some shenanigans on the bus where they try to fetch two lines when you ask for one. So there’s ostensibly some benefit of aligning data particularly on linear scans to 128 byte alignment for cold cache access.
KeplerBoya minute ago
It's not just Intel is it, AMD is also using 64 byte cache lines afaik.
rcoveson12 hours ago
But there's a reason that caches are always sized in powers of two as well, and that same reason is applicable to high-performance ring buffers: Division by powers of two is easy and easy is fast. It's reliably a single cycle, compared to division by arbitrary 32bit integers which can be 8-30 cycles depending on CPU.
Also, there's another benefit downstream of that one: Powers of two work as a schelling point for allocations. Picking powers of two for resizable vectors maximizes "good luck" when you malloc/realloc in most allocators, in part because e.g. a buddy allocator is probably also implemented using power-of-two allocations for the above reason, but also for the plain reason that other users of the same allocator are more likely to have requested power of two allocations. Spontaneous coordination is a benefit all its own. Almost supernatural! :)
loeg8 hours ago
Fwiw in this application you would never need to divide by an arbitrary integer each time; you'd pick it once and then plumb it into libdivide and get something significantly cheaper than 8-30 cycles.
kevin_thibedeau11 hours ago
powers-of-two are problematic with growable arrays on small heaps. You risk ending up with fragmented space you can't allocate unless you keep growth less than 1.61x, which would necessitate data structures that can deal with arbitrary sizes.
aidenn013 hours ago
Non-power-of-two is only really feasible of the total number of inserts will fit in your post/ack counters. Otherwise you have to implement overflow manually which may or may not be possible to do with the available atomic primitives on your architecture.
I first encountered this structure at a summer internship at a company making data switches.
tom_11 hours ago
A couple of the comments to the article suggest using 64-bit numbers, which is exactly the right solution. 2^64 nanoseconds=584.55 years - overflow is implausible for any realistic use case. Even pathological cases will struggle to induce wraparound at a human timescale.
(People will probably moan at the idea of restarting the process periodically rather than fixing the issue properly, but when the period would be something like 50 years I don't think it's actually a problem.)
ale423 hours ago
> using 64-bit numbers, which is exactly the right solution
On a 64-bit platform, sure. When you're working on ring buffers with an 8-bit microcontroller, using 64-bit numbers would be such an overhead that nobody would even think of it.
thaumasiotes6 hours ago
> but when the period would be something like 50 years I don't think it's actually a problem
I think you have that backwards. If something needs to be done every week, it will get done every week. That's not a problem.
If something needs to be done every fifty years, you'll be lucky if it happens once.
reincarnate0x143 hours ago
I agree with that sentiment in general but even though I've seen systems in continuous operation for 15 years, I've never seen anything make it to 20. I wouldn't write something with the external expectation it never made it that far, but in practical terms, that's probably about as safe as it gets. Even like embedded medical devices expect to get restarted every now and again.
Just as an example the Voyager computers have been restarted and that's been almost 60 years.
tom_6 hours ago
My parting shot was slightly tongue in cheek, apologies. Fifty years is a long time. The process, whatever it is, will have been replaced or otherwise become irrelevant long before the period is up. 64 bits will be sufficient.
[deleted]13 hours agocollapsed
ErroneousBosh2 hours ago
> The author says that non-power-of-two is not possible, but I'm pretty sure it is if you use a conditional instead of integer modulus.
I don't see why it wouldn't be, it's just computationally expensive to take the modulo value of the pointer rather than just masking off the appropriate number of bits.
azemetre13 hours ago
Your link has an invalid cert FYI, but do appreciate the knowledge drop. Rung buffers are some of the cooler data structures out there.
RossBencinaan hour ago
Unfortunately the original source is now behind a sign-in-wall.
zephen10 hours ago
> It is not just a way of writing ring buffers. It's a way of implementing concurrent non-blocking single-reader single-writer atomic ring buffers with only atomic load and store (and memory barriers).
That may or may not be part of the actual definition of a ring buffer, but every ring buffer I have written had those goals in mind.
And the first method mentioned in the article fully satisfies this, except for the one missing element mentioned by the author. Which in practice, often is not only not a problem, but simplifies the logic so much that you make up for it in code space.
Or, for example, say you have a 256 character buffer. You really, really want to make sure you don't waste that one character. So you increase the size of your indices. Now they are 16 bits each instead of 8 bits, so you've gained the ability to store 256 bytes by having 260 bytes of data, rather than 255 bytes by having 258 bytes of data.
Obviously, if you have a 64 byte buffer, there is no such tradeoff, and the third example wins (but, whether your are doing the first or third example, you still have to mask the index data off at some point, whether it's on an increment or a read).
> The author says that non-power-of-two is not possible, but I'm pretty sure it is if you use a conditional instead of integer modulus.
There's "not possible" and then "not practical."
Sure, you could have a 50 byte buffer, but now, if your indices are ever >= 50, you're subtracting 50 before accessing the array, so this will increase the code space (and execution time).
> The [index size > array size] technique is also widely known in FPGA/hardware circles
Right, but in those hardware circles, power-of-two _definitely_ matters. You allocate exactly one extra bit for your pointers, and you never bother manually masking them or taking a modulo or anything like that -- they simply roll over.
If you really, really need to construct something like a 6 entry FIFO in hardware, then you have techniques available to you that mere mortal programmers could not use efficiently at all. For example, you could construct a drop-through FIFO, where every element traverses every storage slot (with a concomitant increase in minimum latency to 6 clock cycles), or you could construct 4 bit indices that counted 0-1-2-3-4-5-8-9-10-11-12-13-0-1-2 etc.
Most ring buffers, hardware or software, are constructed as powers of two, and most ring buffers either (a) have so much storage that one more element wouldn't make any difference, or (b) have the ability to apply back pressure, so one more element wouldn't make any difference.
cuno2 hours ago
This stuff dates way, way before 2004.
For non-power of two, just checked our own very old circular byte buffer library code and using the notation from this article, it is:
entriesAllocated() { return ((wrPtr-rdPtr+2*bufSize) % (2*bufSize)); }
remainingSpace() { return bufSize - entriesAllocated(); }
isEmpty() { return (entriesAllocated()==0); }
isFull() { return (entriesAllocated()==bufSize); }
incWr(int n) { wrPtr = (wrPtr+n) % (2*bufSize); }
incRd(int n) { rdPtr = (rdPtr+n) % (2*bufSize); }
The 2*bufSize gives you an extra bit (beyond representing bufSize) that lets you disambiguate empty vs full. And if it is a constant power of two (e.g. via C++ template), then you can see how this just compiles into a bitmask instead, like the author's version. You read and write the buffer at (rdPtr%bufSize) and (wrPtr%bufSize) respectively.atq21192 hours ago
It's a silly offhand remark at the end of the article, but anybody who is genuinely interested in whether they've been tying their shoes wrong will enjoy Ian's shoelace site: https://www.fieggen.com/shoelace/
Someone14 hours ago
> So there I was, implementing a one element ring buffer. Which, I'm sure you'll agree, is a perfectly reasonable data structure.
It is, but, IMO, shouldn’t use the code for “a n-element ring buffer, with n set to 1”, similarly to how an array of booleans in many languages shouldn’t be implemented as “an arrayof Foos, with Foo set to bool”.
C++ has std::bitset and std::vector and Java similarly has BitSet and Array because using the generic code for arrays of bits is too wasteful.
Similarly, a one-element ring buffer is either full or it is empty. Why use two indexes to encode a single boolean?
cpgxiii13 hours ago
> C++ has std::bitset and std::vector and Java similarly has BitSet and Array because using the generic code for arrays of bits is too wasteful.
Rather infamously, C++ tried to be clever here and std::vector<bool> is not just a vector-of-bools but instead a totally different vector-ish type that lacks many of the important properties of every other instantiation of std::vector. Yes, a lot of the time you want the space efficiency of a dynamic bitset, rather than wasting an extra 7 bits per element. But also quite often you do want the behavior of a "real" std::vector for true/false values, and then you have to work around it manually (usually via std::vector<uint8_t> or similar) to get the expected behavior.
jsnell14 hours ago
It was for a dynamically growing ring buffer that also did short-object optimization. The natural implementation was to have the capacity and the offsets stored in fixed locations and with a fixed width, and have the variable part be a union of pointer or inline byte buffer.
Depending on the element width, you'd have space for different amounts of data in the inline buffer. Sometimes 1, sometimes a few more. Specializing for a one-element inline buffer would be quite complex with limited gains.
In retrospect trying to use that as a running gag for the blog post did not work well without actually giving the full context, but the full context would have been a distraction.
andrepd14 hours ago
> C++ has std::bitset and std::vector
Notably, this is not the case. C++ std::vector is specialised for bools to pack bits into words, causing an untold array (heh) of headaches.
And "wasteful" is doing a lot of lifting here. In terms of memory usage? Yes. In terms of CPU? The other way around.
mbel13 hours ago
> In terms of CPU? The other way around.
That depends on your architecture and access pattern. In case of sequential access, packed bools may perform better due to arithmetic being usually way cheaper than memory operations.
ekropotin13 hours ago
I’m jealous of people, who have to write ring buffers for work.
It feels like 90% swe jobs these days are about writing CRUD wrappers.
avadodin12 hours ago
Sorry.
Mostly Type 1 and overflow is a diagnostic log at most. Losing all stale unprocessed data and leaving a ready empty buffer behind is often the desired outcome.
Type 3 is probably banned on most codebases because of the integer overflow.
zephen6 hours ago
> Losing all stale unprocessed data and leaving a ready empty buffer behind is often the desired outcome.
Yeah, the Type 3 example could conceivably make it so that you intermix old and new data if you overflow, rather than just dumping a whole buffer.
Especially when your full() function checks for exact equality, like the one in the article does.
And if you remove the asserts, and then somehow underflow? God help you. You'll be pulling 4 billion entries you never actually stored out of the buffer, just repeating previously stored garbage over and over.
> Type 3 is probably banned on most codebases because of the integer overflow.
Not only this, but the purported code reduction benefits associated with type 3 are only superficial, and won't actually appear in any assembly listing.
Krssst9 hours ago
Unsigned integer arithmetic operations don't overflow but are done modulo 2^n (https://en.cppreference.com/w/c/language/operator_arithmetic...). The author does use unsigned integers so I don't think there is a problem there.
Signed integer overflow is definitely a problem however. Something as simple as incrementing a user-provided int can lead to UB (if the user provides INT_MAX).
RealityVoid7 hours ago
Banned is a bit strong, maybe discouraged. MISRA might yell but it's valid technique, IMO, unsigned integer overflow will be fine.
Neywiny10 hours ago
And yet here I sit, writing ring buffers, and never thinking about this idea. Probably because of the power of two issue. Which isn't actually a problem because as he points out, who would do that? But it makes me think that it's a restriction that it just isn't.
But in all honesty, look for more embedded jobs, then. We can certainly use the help.
nathan_douglas7 hours ago
What do you work with (if you don't mind answering)? I'm looking for a change and like low-level stuff about as much as I like any other level. I've done some cycle-accurate NES emulation and VM implementation stuff - I'm not much of a DSA guy but performance and efficiency appeal to me.
ekropotin9 hours ago
For some unexplainable reason, CRUD job’s pay is better than embedded, on average.
Neywiny9 hours ago
I mean idk, I'm living comfortably and as the adage says, not working a day in my life. But if you're at a spot where you need the pay more than you want to write ring buffers, I understand.
RealityVoid13 hours ago
Jokes on me, when I need them, I don't feel like writing them so I just pick up an old one and tweak it. Or just tell Claude to build me one and it one shots it.
nly2 hours ago
Most people implement them now in my field using mmap tricks so the CPU can do the wraparound for you in virtual memory.
Makes the code trivial
z3t43 hours ago
Why would you ever want a data structure that wraps around!? What a headache! Is it a memory constraint or optimization!? All I can think about is a physical knob where you want to know what position it is in.
danhau2 hours ago
They are efficient FIFOs (queues). You‘ll find them in many places. I know them from multimedia / audio, where you often have unsynchronized readers and writers.
In the audio domain, the reader and weiter are usually allowed to trample over each other. If you‘ve ever gamed on a PC, you might have heard this. When a game freezes, sometimes you hear a short loop of audio playing until the game unfreezes. That‘s a ringbuffer whose writer has stopped, but the async reader is still reading the entire buffer.
Zig‘s “There are too many ring buffer implementations in the standard library“ might also be interesting:
Mikhail_Edoshin5 hours ago
Technically each side needs an index plus a single bit. The bit is a counter, you increment it on every wrap. It overflows, but this is correct, we only need the last bit. Initially it is 0. By comparing the indexes and the bit you tell apart all cases and do not lose an entry.
(I think this was published in one of Llang's papers but in a rather obscure language.)
grumbelbart24 hours ago
One of the comments in the article proposes that: Just wrap both counters at 2capacity (instead of capacity or UINT_MAX).
Mikhail_Edoshin4 hours ago
Which does that and that's what Llang suggests as well, I remember 2 in some power in his formula. I myself find the separate one-bit counter easier to understand: each side counts pages, but they don't need the full number, only the difference between their counters and the difference can be at most one, so one bit is sufficient. If the counters are same, the actors are on the same page, if they are different, then the writer is one page ahead.
dang15 hours ago
Related. Others?
I've been writing ring buffers wrong all these years - https://news.ycombinator.com/item?id=13175832 - Dec 2016 (167 comments)
spacechild1an hour ago
> All of those seem like non-issues. What kind of a monster would make a non-power of two ring anyway?
Huh? Anytime you want to restrict the buffer to a specific size, you will have to support non-power-of-two capacities. There are cases where the capacity of the ring buffer determines the latency of the system, e.g. an audio ringbuffer or a network jitter buffer.
codeworse3 days ago
As far as I know, the last approach is the only way to implement efficient lock-free ring-buffer
zephen10 hours ago
The middle approach is the only one that is not lock-free.
The first approach is lock-free, but as the author says, it wastes an element.
But here's the thing. If your element is a character, and your buffer size is, say, 256 bytes, and you are using 8-bit unsigned characters for indices, the one wasted byte is less than one percent of your buffer space, and also is compensated for by the simplicity and reduced code size.
fullstop7 hours ago
I've used the "Waste an element" one for ages on microcontrollers where I don't want to deal with the overhead in an ISR.
zephen5 hours ago
Agreed.
The article author claims that the "don't waste an element" code is also more efficient, but that claim seems to be based on a hard-on about the post-increment operator, rather than any kind of dive into the cyclometric complexity, or even, y'know, just looking at the assembler output from the compiler.
mrcode00714 hours ago
There is one more way that is truly lock free. Most lock free implementations relying on atomic compare and swap instructions are not lock free afaik; they have a lock on the cache line in the CPU (in a way you go away from global lock to many distributed locks).
There is one more mechanism that allows implementing ring buffers without having to compare head and tail buffers at all (and doesn’t rely on counters or empty/full flags etc) that piggybacks on the cache consistency protocol
dooglius13 hours ago
That's not how "lock free" is defined/used. If you are considering the MESI M state to be a "lock" then you also have to grant that any write instruction is a "lock".
wat1000013 hours ago
Those hardware-level locks are typically not considered because they work quite differently. A standard software mutex can cause other threads to block indefinitely if, for example, the thread holding the mutex gets preempted for a long time. "Lock free" isn't really about the locks, it's about a guarantee that the system makes progress.
In this sense, the hardware locks used for atomic instructions don't really count, because they're implemented such that they can only be held for a brief, well defined time. There's no equivalent to suspending a thread while it holds a lock, causing all other threads to wait for an arbitrary amount of time.
spockz14 hours ago
Interesting! Do you know of an example implementation of this?
gpderetta3 hours ago
That's how TCP sequence numbers work as well.
kybernetikos14 hours ago
Every implementation of "the lmax disrupter" I've come across uses this trick.